Dictionary Creation Via List Comprehension
Mon 10 August 2026
keys = ["a", "b"]
values = [1, 2]
data = {k: v for k, v in zip(keys, values)}
Score: 10
Category: chapter9_list_comprehension
keys = ["a", "b"]
values = [1, 2]
data = {k: v for k, v in zip(keys, values)}
Score: 10
Category: chapter9_list_comprehension